Integrand size = 28, antiderivative size = 295 \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{(d+e x)^3} \, dx=\frac {10 b^3 (b d-a e)^2 x \sqrt {a^2+2 a b x+b^2 x^2}}{e^5 (a+b x)}+\frac {(b d-a e)^5 \sqrt {a^2+2 a b x+b^2 x^2}}{2 e^6 (a+b x) (d+e x)^2}-\frac {5 b (b d-a e)^4 \sqrt {a^2+2 a b x+b^2 x^2}}{e^6 (a+b x) (d+e x)}-\frac {5 b^4 (b d-a e) (d+e x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}{2 e^6 (a+b x)}+\frac {b^5 (d+e x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}{3 e^6 (a+b x)}-\frac {10 b^2 (b d-a e)^3 \sqrt {a^2+2 a b x+b^2 x^2} \log (d+e x)}{e^6 (a+b x)} \]
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Time = 0.11 (sec) , antiderivative size = 295, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {660, 45} \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{(d+e x)^3} \, dx=-\frac {5 b \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^4}{e^6 (a+b x) (d+e x)}+\frac {\sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^5}{2 e^6 (a+b x) (d+e x)^2}-\frac {10 b^2 \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^3 \log (d+e x)}{e^6 (a+b x)}+\frac {b^5 \sqrt {a^2+2 a b x+b^2 x^2} (d+e x)^3}{3 e^6 (a+b x)}-\frac {5 b^4 \sqrt {a^2+2 a b x+b^2 x^2} (d+e x)^2 (b d-a e)}{2 e^6 (a+b x)}+\frac {10 b^3 x \sqrt {a^2+2 a b x+b^2 x^2} (b d-a e)^2}{e^5 (a+b x)} \]
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Rule 45
Rule 660
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {a^2+2 a b x+b^2 x^2} \int \frac {\left (a b+b^2 x\right )^5}{(d+e x)^3} \, dx}{b^4 \left (a b+b^2 x\right )} \\ & = \frac {\sqrt {a^2+2 a b x+b^2 x^2} \int \left (\frac {10 b^8 (b d-a e)^2}{e^5}-\frac {b^5 (b d-a e)^5}{e^5 (d+e x)^3}+\frac {5 b^6 (b d-a e)^4}{e^5 (d+e x)^2}-\frac {10 b^7 (b d-a e)^3}{e^5 (d+e x)}-\frac {5 b^9 (b d-a e) (d+e x)}{e^5}+\frac {b^{10} (d+e x)^2}{e^5}\right ) \, dx}{b^4 \left (a b+b^2 x\right )} \\ & = \frac {10 b^3 (b d-a e)^2 x \sqrt {a^2+2 a b x+b^2 x^2}}{e^5 (a+b x)}+\frac {(b d-a e)^5 \sqrt {a^2+2 a b x+b^2 x^2}}{2 e^6 (a+b x) (d+e x)^2}-\frac {5 b (b d-a e)^4 \sqrt {a^2+2 a b x+b^2 x^2}}{e^6 (a+b x) (d+e x)}-\frac {5 b^4 (b d-a e) (d+e x)^2 \sqrt {a^2+2 a b x+b^2 x^2}}{2 e^6 (a+b x)}+\frac {b^5 (d+e x)^3 \sqrt {a^2+2 a b x+b^2 x^2}}{3 e^6 (a+b x)}-\frac {10 b^2 (b d-a e)^3 \sqrt {a^2+2 a b x+b^2 x^2} \log (d+e x)}{e^6 (a+b x)} \\ \end{align*}
Time = 1.07 (sec) , antiderivative size = 248, normalized size of antiderivative = 0.84 \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{(d+e x)^3} \, dx=\frac {\sqrt {(a+b x)^2} \left (-3 a^5 e^5-15 a^4 b e^4 (d+2 e x)+30 a^3 b^2 d e^3 (3 d+4 e x)+30 a^2 b^3 e^2 \left (-5 d^3-4 d^2 e x+4 d e^2 x^2+2 e^3 x^3\right )+15 a b^4 e \left (7 d^4+2 d^3 e x-11 d^2 e^2 x^2-4 d e^3 x^3+e^4 x^4\right )+b^5 \left (-27 d^5+6 d^4 e x+63 d^3 e^2 x^2+20 d^2 e^3 x^3-5 d e^4 x^4+2 e^5 x^5\right )-60 b^2 (b d-a e)^3 (d+e x)^2 \log (d+e x)\right )}{6 e^6 (a+b x) (d+e x)^2} \]
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Time = 2.73 (sec) , antiderivative size = 301, normalized size of antiderivative = 1.02
method | result | size |
risch | \(\frac {\sqrt {\left (b x +a \right )^{2}}\, b^{3} \left (\frac {1}{3} b^{2} e^{2} x^{3}+\frac {5}{2} x^{2} a b \,e^{2}-\frac {3}{2} b^{2} d e \,x^{2}+10 a^{2} e^{2} x -15 a b d e x +6 b^{2} d^{2} x \right )}{\left (b x +a \right ) e^{5}}+\frac {\sqrt {\left (b x +a \right )^{2}}\, \left (\left (-5 e^{4} a^{4} b +20 d \,e^{3} a^{3} b^{2}-30 d^{2} e^{2} a^{2} b^{3}+20 a \,b^{4} d^{3} e -5 d^{4} b^{5}\right ) x -\frac {a^{5} e^{5}+5 a^{4} b d \,e^{4}-30 a^{3} b^{2} d^{2} e^{3}+50 a^{2} b^{3} d^{3} e^{2}-35 a \,b^{4} d^{4} e +9 b^{5} d^{5}}{2 e}\right )}{\left (b x +a \right ) e^{5} \left (e x +d \right )^{2}}+\frac {10 \sqrt {\left (b x +a \right )^{2}}\, b^{2} \left (a^{3} e^{3}-3 a^{2} b d \,e^{2}+3 a \,b^{2} d^{2} e -b^{3} d^{3}\right ) \ln \left (e x +d \right )}{\left (b x +a \right ) e^{6}}\) | \(301\) |
default | \(\frac {\left (\left (b x +a \right )^{2}\right )^{\frac {5}{2}} \left (-120 \ln \left (e x +d \right ) b^{5} d^{4} e x -27 b^{5} d^{5}-3 a^{5} e^{5}-15 a^{4} b d \,e^{4}+90 a^{3} b^{2} d^{2} e^{3}-150 a^{2} b^{3} d^{3} e^{2}+105 a \,b^{4} d^{4} e +120 a^{3} b^{2} d \,e^{4} x -30 a^{4} b \,e^{5} x +360 \ln \left (e x +d \right ) a \,b^{4} d^{3} e^{2} x +60 \ln \left (e x +d \right ) a^{3} b^{2} e^{5} x^{2}-60 \ln \left (e x +d \right ) b^{5} d^{3} e^{2} x^{2}+60 \ln \left (e x +d \right ) a^{3} b^{2} d^{2} e^{3}-180 \ln \left (e x +d \right ) a^{2} b^{3} d^{3} e^{2}+180 \ln \left (e x +d \right ) a \,b^{4} d^{4} e -180 \ln \left (e x +d \right ) a^{2} b^{3} d \,e^{4} x^{2}+180 \ln \left (e x +d \right ) a \,b^{4} d^{2} e^{3} x^{2}-60 x^{3} a \,b^{4} d \,e^{4}+120 x^{2} a^{2} b^{3} d \,e^{4}-165 x^{2} a \,b^{4} d^{2} e^{3}-360 \ln \left (e x +d \right ) a^{2} b^{3} d^{2} e^{3} x +120 \ln \left (e x +d \right ) a^{3} b^{2} d \,e^{4} x -5 x^{4} b^{5} d \,e^{4}+60 x^{3} a^{2} b^{3} e^{5}+20 x^{3} b^{5} d^{2} e^{3}-60 \ln \left (e x +d \right ) b^{5} d^{5}+6 b^{5} d^{4} e x +2 x^{5} e^{5} b^{5}+15 x^{4} a \,b^{4} e^{5}+63 x^{2} b^{5} d^{3} e^{2}-120 x \,a^{2} b^{3} d^{2} e^{3}+30 x a \,b^{4} d^{3} e^{2}\right )}{6 \left (b x +a \right )^{5} e^{6} \left (e x +d \right )^{2}}\) | \(502\) |
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Time = 0.27 (sec) , antiderivative size = 416, normalized size of antiderivative = 1.41 \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{(d+e x)^3} \, dx=\frac {2 \, b^{5} e^{5} x^{5} - 27 \, b^{5} d^{5} + 105 \, a b^{4} d^{4} e - 150 \, a^{2} b^{3} d^{3} e^{2} + 90 \, a^{3} b^{2} d^{2} e^{3} - 15 \, a^{4} b d e^{4} - 3 \, a^{5} e^{5} - 5 \, {\left (b^{5} d e^{4} - 3 \, a b^{4} e^{5}\right )} x^{4} + 20 \, {\left (b^{5} d^{2} e^{3} - 3 \, a b^{4} d e^{4} + 3 \, a^{2} b^{3} e^{5}\right )} x^{3} + 3 \, {\left (21 \, b^{5} d^{3} e^{2} - 55 \, a b^{4} d^{2} e^{3} + 40 \, a^{2} b^{3} d e^{4}\right )} x^{2} + 6 \, {\left (b^{5} d^{4} e + 5 \, a b^{4} d^{3} e^{2} - 20 \, a^{2} b^{3} d^{2} e^{3} + 20 \, a^{3} b^{2} d e^{4} - 5 \, a^{4} b e^{5}\right )} x - 60 \, {\left (b^{5} d^{5} - 3 \, a b^{4} d^{4} e + 3 \, a^{2} b^{3} d^{3} e^{2} - a^{3} b^{2} d^{2} e^{3} + {\left (b^{5} d^{3} e^{2} - 3 \, a b^{4} d^{2} e^{3} + 3 \, a^{2} b^{3} d e^{4} - a^{3} b^{2} e^{5}\right )} x^{2} + 2 \, {\left (b^{5} d^{4} e - 3 \, a b^{4} d^{3} e^{2} + 3 \, a^{2} b^{3} d^{2} e^{3} - a^{3} b^{2} d e^{4}\right )} x\right )} \log \left (e x + d\right )}{6 \, {\left (e^{8} x^{2} + 2 \, d e^{7} x + d^{2} e^{6}\right )}} \]
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\[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{(d+e x)^3} \, dx=\int \frac {\left (\left (a + b x\right )^{2}\right )^{\frac {5}{2}}}{\left (d + e x\right )^{3}}\, dx \]
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Exception generated. \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{(d+e x)^3} \, dx=\text {Exception raised: ValueError} \]
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Time = 0.26 (sec) , antiderivative size = 390, normalized size of antiderivative = 1.32 \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{(d+e x)^3} \, dx=-\frac {10 \, {\left (b^{5} d^{3} \mathrm {sgn}\left (b x + a\right ) - 3 \, a b^{4} d^{2} e \mathrm {sgn}\left (b x + a\right ) + 3 \, a^{2} b^{3} d e^{2} \mathrm {sgn}\left (b x + a\right ) - a^{3} b^{2} e^{3} \mathrm {sgn}\left (b x + a\right )\right )} \log \left ({\left | e x + d \right |}\right )}{e^{6}} - \frac {9 \, b^{5} d^{5} \mathrm {sgn}\left (b x + a\right ) - 35 \, a b^{4} d^{4} e \mathrm {sgn}\left (b x + a\right ) + 50 \, a^{2} b^{3} d^{3} e^{2} \mathrm {sgn}\left (b x + a\right ) - 30 \, a^{3} b^{2} d^{2} e^{3} \mathrm {sgn}\left (b x + a\right ) + 5 \, a^{4} b d e^{4} \mathrm {sgn}\left (b x + a\right ) + a^{5} e^{5} \mathrm {sgn}\left (b x + a\right ) + 10 \, {\left (b^{5} d^{4} e \mathrm {sgn}\left (b x + a\right ) - 4 \, a b^{4} d^{3} e^{2} \mathrm {sgn}\left (b x + a\right ) + 6 \, a^{2} b^{3} d^{2} e^{3} \mathrm {sgn}\left (b x + a\right ) - 4 \, a^{3} b^{2} d e^{4} \mathrm {sgn}\left (b x + a\right ) + a^{4} b e^{5} \mathrm {sgn}\left (b x + a\right )\right )} x}{2 \, {\left (e x + d\right )}^{2} e^{6}} + \frac {2 \, b^{5} e^{6} x^{3} \mathrm {sgn}\left (b x + a\right ) - 9 \, b^{5} d e^{5} x^{2} \mathrm {sgn}\left (b x + a\right ) + 15 \, a b^{4} e^{6} x^{2} \mathrm {sgn}\left (b x + a\right ) + 36 \, b^{5} d^{2} e^{4} x \mathrm {sgn}\left (b x + a\right ) - 90 \, a b^{4} d e^{5} x \mathrm {sgn}\left (b x + a\right ) + 60 \, a^{2} b^{3} e^{6} x \mathrm {sgn}\left (b x + a\right )}{6 \, e^{9}} \]
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Timed out. \[ \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{(d+e x)^3} \, dx=\int \frac {{\left (a^2+2\,a\,b\,x+b^2\,x^2\right )}^{5/2}}{{\left (d+e\,x\right )}^3} \,d x \]
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